(2b^2+2b-4)/(b-3)

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Solution for (2b^2+2b-4)/(b-3) equation:


D( b )

b-3 = 0

b-3 = 0

b-3 = 0

b-3 = 0 // + 3

b = 3

b in (-oo:3) U (3:+oo)

(2*b^2+2*b-4)/(b-3) = 0

2*b^2+2*b-4 = 0

2*(b^2+b-2) = 0

b^2+b-2 = 0

DELTA = 1^2-(-2*1*4)

DELTA = 9

DELTA > 0

b = (9^(1/2)-1)/(1*2) or b = (-9^(1/2)-1)/(1*2)

b = 1 or b = -2

2*(b+2)*(b-1) = 0

(2*(b+2)*(b-1))/(b-3) = 0

( b+2 )

b+2 = 0 // - 2

b = -2

( b-1 )

b-1 = 0 // + 1

b = 1

b in { -2, 1 }

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